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JEE Advanced Model Paper 3 with solutions for online practice
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© examsnet.com
Question : 7
Total: 60
Two elastic balls of masses M and m(M ≫ m) are placed on top of each other with a small gap between them. The balls are dropped on to the ground with the bottom of the lower ball at height h above the ground. The lower ball has a radius Rand the upperball has negligible dimension. The ball of mass m will bounce above the ground to a height ( 2R + nh) where n is
Your Answer:
Validate
Solution:
u =
√
2
g
h
During collision between the balls, speed of M does not change much ( M ≫ m) . And, relative speed of separation = relative speed of approach.
⇒ The smaller bounces off with speed 3u .
∴ Height attained by the ball above the ground is ,
H = 2R +
(
3
u
)
2
2
g
= 2R + 9h [
u
2
= 2gh]
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