Δx at 0 = d [path difference is maximum at O] So, if d =
7λ
2
, O will be a minima. If d = λ , O will be maxima, if d =
5λ
2
, O will be minima and hence intensity is minimum If d = 4.8 λ , then total 10 minima can be observed on the screen , 5 above O and 5 below O , which correspond to Δx = ±