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JEE Advanced Model Paper 4 with solutions for online practice
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© examsnet.com
Question : 49
Total: 54
The values of x satisfying
s
i
n
−
1
x +
s
i
n
−
1
(1 - x) =
c
o
s
−
1
x is/are
0
1
2
1
2
Validate
Solution:
π
2
−
c
o
s
−
1
x
+
π
2
−
c
o
s
−
1
(1 - x) =
c
o
s
−
1
x
2
c
o
s
−
1
x
= π -
c
o
s
−
1
(1 - x)
c
o
s
−
1
2
x
2
- 1 =
c
o
s
−
1
(x - 1)
2
x
2
- 1 = x - 1 ,
2
x
2
- x > 0
x (2x - 1) = 0 , x = 0 ,
1
2
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