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JEE Advanced Model Paper 5 with solutions for online practice
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© examsnet.com
Question : 12
Total: 54
One end of an elastic string of natural length
I
0
and force constant k N/m is fixed to a point on a smooth horizontal surface and the other end is attached to a particle of mass m lying on the surface. The particle is pulled to a distance 2
I
0
from thefixed point and then released from rest. Time period (in s) for complete oscillation of the particle will be n. Find the value of n. (m = 1 kg ,
√
k
- 4 = 2π)
Your Answer:
Validate
Solution:
Answer (1)
Motion will be combination of SHM + Uniform motion
T = 2π
√
m
K
+
4
a
I
0
v
m
a
x
v
m
a
x
= ω
I
0
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