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JEE Advanced Model Paper 7 with solutions for online practice
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© examsnet.com
Question : 25
Total: 66
If f(x) =
Lt
x
→
∞
A
n
=
n
Σ
r
=
0
(
t
a
n
x
2
r
+
1
+
t
a
n
3
x
2
r
+
1
)
1
−
t
a
n
2
x
2
r
+
1
then
A
n
=
s
i
n
x
2
n
+
1
c
o
s
x
2
n
+
1
c
o
s
x
2
n
A
n
= tanx - tan
x
2
n
+
1
Lt
x
→
0
f
(
x
)
−
s
i
n
x
x
3
=
2
3
Lt
x
→
∞
f
(
x
)
−
s
i
n
x
x
3
=
1
3
Validate
Solution:
A
n
=
n
Σ
r
=
0
s
i
n
x
2
r
+
1
c
o
s
x
2
r
+
1
c
o
s
x
2
r
=
n
Σ
r
=
0
(
t
a
n
x
2
r
−
t
a
n
x
2
r
+
1
)
= tanx - tan
x
2
r
+
1
f(x) = tanx
∴ f(x) =
Lt
x
→
0
t
a
n
x
−
s
i
n
x
x
3
=
Lt
x
→
0
s
i
n
x
(
1
−
c
o
s
x
)
x
.
x
2
=
1
2
© examsnet.com
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