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JEE Advanced Model Paper 7 with solutions for online practice
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© examsnet.com
Question : 50
Total: 66
6 moles of ozone is partially converted into oxygen till the number of ozone and oxygenmolecules become equal. Then
Masses of ozone & oxygen in the mixture are equal
The mixture contains 18 moles of oxygen atoms
The mixture contains 3.6 moles of oxygen
Ozone and oxygen gasses are 3:2 mass ratio in the final mixture
Validate
Solution:
2
O
3
→
3
O
2
6 - 2x → 3x
6 - 2x = 3x ⇒ x = 1.2
O
3
moles left = 6 - 2.4 = 3.6
O
2
moles formed = 3.6
Mass ratio of ozone to oxygen = (3.6 × 48) : (3.6 × 32) = 3 : 2
No. of ‘O’ atoms = (3.6 × 3) + (3.6 × 2) = 18
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