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JEE Advanced Model Paper 8 with solutions for online practice
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© examsnet.com
Question : 1
Total: 84
0.84g of a divalent metal carbonate required 80ml of 0.125 M
H
2
S
O
4
to react completely. Theatomic weight of metal is
42
84
12
24
Validate
Solution:
0.84
E
=
0.25
×
80
1000
Equivalent weight of metal carbonate = 42 =
E
M
+
E
C
O
3
2
−
=
E
M
+ 30
∴ Equivalent weight of metal = 12
∴ Atomic weight of metal is = 12 × 2 = 24
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