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JEE Advanced Model Paper 8 with solutions for online practice
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© examsnet.com
Question : 64
Total: 84
A conducting rod of length L is moving on a horizontal smooth surface. Magneticfield in the region is vertically downward and of magnitude
B
0
. If centre of mass of therod is translating with velocity
v
0
and rod rotates about centre of mass with angularvelocity
v
0
/L then potential difference between points O and A will be
5
8
B
0
v
0
L
3
8
B
0
v
0
L
1
8
B
0
v
0
L
1
2
B
0
v
0
L
Validate
Solution:
Potential difference between O and A is Blv
Where v is the velocity of the mid-point of O and A
Thus , e =
B
0
(
L
2
)
[
v
0
+
L
4
(
v
0
L
)
]
=
5
B
0
L
v
0
8
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