For case I, The potential difference of the uniform wire, V =240 V The resistance of the uniform wire, R1 = 36 Ω The power dissipation in the first case, P1=
V2
R1
=
(240)2
36
For case II, The resistance of each half, R2=
R1
2
=
36
2
=18Ω P2=
V2
R2
+
V2
R2
=
(240)2
18
+
(240)2
18
=
(240)2
9
Thus, the ratio of the total power dissipation in the first case to thesecond case