Given, the mass of the steel rod, m = 2 kg
The length of the steel rod, I = 0.6 m
According to question, the diagram can be as shown below
By using the energy conservation,
mgl=lω2 mgl=××ω2 ⇒
ω= As we know the relation between the linear speed and angularspeed,
v=ωr=ωl=√6gl Substituting the values in the above equation, we get
v=√6×10×0.6=6 m / s
Hence, the speed of the free end of the rod when it passes throughits lowest position is 6 m/s.