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JEE Main 10 April 2016 Paper
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© examsnet.com
Question : 8
Total: 90
A Carnot freezer takes heat from water at 0°C inside it and rejects it to the room at a temperature of 27°C. The latent heat of iceis
336
×
10
3
J
k
g
−
1
. If 5 kg of water at 0°C is converted into ice at 0°C by the freezer, then the energy consumed by the freezer is close to :
1.67
×
10
5
J
1.68
×
10
6
J
1.51
×
10
5
J
1.71
×
10
7
J
Validate
Solution:
heat required to freeze 5 kg water
5
×
336
×
10
3
=
1680
×
10
3
Joule
⇒
Q
1
=
1680
KJ
for carnot's cycle
Q
2
Q
1
=
T
2
T
1
Q
2
1680
=
=
300
273
Q
2
=
1680
×
300
273
KJ
W
=
Q
2
−
Q
1
=
1680
(
300
273
−
1
)
=
1680
×
27
273
×
10
3
J
=
166.15
×
10
3
J
=
1.66
×
10
5
K
J
© examsnet.com
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