Given, carrier signal, C(t)=25sin(2.512×1010t) Message signal, m(t)=5sin(1.57×108t) Angular frequency of the message signal, ωm=1.57×108rads−1 Frequency of the message signal, of the message fm=
ωm
2π
Substituting the values in the above equation, we get fm=
1.57×108
2π
Hz Bandwidth of the modulated signal is β=2fm Substituting the values in the above equation, we get β=2(
1.57×10B
2π
) β=50MHz Hence, the bandwidth of the modulated signal is 50MHz.