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JEE Main 18 March 2021 Shift 1 Solved Paper

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Question : 59

Total: 90

For the reaction,
2Fe3+(aq)+2l−(aq)⟶2Fe2+(aq)+I2(s)
The magnitude of the standard molar Gibbs free energy change,
∆,Gm∘=−. . . . . . . . . . kJ
(Round off to the nearest integer).

EFe2+∕Fe(s)∘=−0.440V;	EFe3+/Fe(s)∘=−0.036V
EI2/2I−=0.539V;	F=96500C

[18 Mar 2021 Shift 1]

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