Given, height of the TV transmission antenna, H=20m Initial range of the antenna at the ground level, R=√2RH Final range of the antenna at the height of 5m, R′=√2RH+√2RH′ Percentage increase in the antenna range, % range =
R′−R
R
×100 =
√2RH′
√2RH
×100=
√H′
√H
×100 =
√5
√20
×100=50% Hence, the value of n to the nearest integer is 50 .