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JEE Main 2013 Question Paper
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© examsnet.com
Question : 6
Total: 90
Four successive members of the first row transition elements are listed below with atomic numbers. Which one of them is expected to have the highest
E
0
M
3
+
∕
M
2
+
value?
Mn(Z = 25)
Fe(Z = 26)
Co(Z = 27)
Cr(Z = 24)
Validate
Solution:
Reduction potential of all species:
E
0
M
3
+
∕
M
+
2
=
1.57
V
E
0
F
e
3
+
∕
F
e
+
2
=
0.77
V
E
0
C
o
3
+
∕
C
o
+
2
=
1.97
V
E
0
C
r
3
+
∕
C
r
+
2
=
−
0.41
V
from their standard reduction potential it can be seen that Co has highest tendency to reduce into +2 oxidation state.
Hence, option C is correct.
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