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JEE Main 2014 Question Paper
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© examsnet.com
Question : 10
Total: 90
In a large buildings,there are 15 bulbs of 40 W,5 bulbs of 100 W,5 fans of 80 W and 1 heater of 1kW. The voltage of the electric mains is 220V. The minimum capacity of the main fuse of the building will be:
12 A
14 A
8 A
10 A
Validate
Solution:
Item
No.
Power
40 W bulb
15
600 watt
100 W bulb
5
500 watt
80 W fan
5
400 Watt
1000 W heater
1
1000 Watt
Total Wattage=2500 Watt
So current capacity i
=
P
V
=
2500
220
=
125
11
=
11.36
≅
12
Amp.
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