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JEE Main 2014 Question Paper
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© examsnet.com
Question : 25
Total: 90
The radiation corresponding to 3→ 2 transition of hydrogen atom falls on a metal surface to produce photoelectrons. These electrons are made to enter field to
3
×
10
−
4
T.If the radius of the largest circular path followed by these electrons is 10.0 mm,the work function of the metal is close to :
0.8 eV
1.6 eV
1.8 eV
1.1 eV
Validate
Solution:
mv = qBR
K
E
(
m
a
x
)
=
(
m
v
)
2
2
m
=
0.8
e
V
h
v
=
13.6
[
1
4
−
1
9
]
∴
w
=
h
v
−
K
E
(
m
a
x
)
13.6
5
36
−
0.8
=
1.1
e
V
© examsnet.com
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