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JEE Main 2014 Question Paper
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© examsnet.com
Question : 8
Total: 90
A student measured the length of a rod and wrote it as 3.50 cm.Which instrument did he use to measure it?
A screw gauge having 100 division in the circular scale and pitch as 1 mm
A screw guage having 50 division in the circular scale and pitch as 1mm
A meter scale
A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 division in 1 cm
Validate
Solution:
Least count of vernier calliper is
1
10
mm = 0.1mm = 0.01cm
© examsnet.com
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