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JEE Main 2016 Question Paper
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© examsnet.com
Question : 2
Total: 90
2-chloro-2-methylpentane on reaction with sodium methoxide in methanol yields
(a).
C
2
H
5
C
H
2
C
H
3
|
C
|
C
H
3
−
O
C
H
3
(b)
C
2
H
5
C
H
2
C
|
C
H
3
=
C
H
2
(c)
C
2
H
5
C
H
=
C
|
C
H
3
−
C
H
3
2-chloro-2-methylpentane on reaction with sodium methoxide in methanol yields<br><div class="hscrollenable">(a).
C
2
H
5
C
H
2
C
H
3
|
C
|
C
H
3
−
O
C
H
3
<br> <br>(b)
C
2
H
5
C
H
2
C
|
C
H
3
=
C
H
2
<br> <br> (c)
C
2
H
5
C
H
=
C
|
C
H
3
−
C
H
3
2-chloro-2-methylpentane on reaction with sodium methoxide in methanol yields
(a).
C
2
H
5
C
H
2
C
H
3
|
C
|
C
H
3
−
O
C
H
3
(b)
C
2
H
5
C
H
2
C
|
C
H
3
=
C
H
2
(c)
C
2
H
5
C
H
=
C
|
C
H
3
−
C
H
3
(a) and (c)
(a) and (c)
(c) only
(c) only
(a) and (b)
(a) and (b)
All of these
All of these
Answer Type :
Checkbox
Radio
Table Radio
Text Box
No Choice
Correct Answer :
1
Has Para?
Yes
No
Verified?
Yes
No
Solution :
When tert -alkyl halides are used in Williamson synthesis elimination occurs rather than substitution resulting into formation af alkene. Here alkoxide jon abstract one of the
β
hydrogen atom along with acting as a nucleophile.
C
H
3
−
C
H
2
−
C
H
2
−
C
H
3
|
C
|
C
l
−
C
H
3
+
N
a
+
O
C
H
3
2-chloro-2-methylpentane
C
H
2
O
H
→
C
H
3
C
H
2
−
H
|
C
=
C
H
3
|
C
−
C
H
3
+
C
H
3
O
H
+
N
a
B
r
2-Methyl-pent-2-ene
When tert -alkyl halides are used in Williamson synthesis elimination occurs rather than substitution resulting into formation af alkene. Here alkoxide jon abstract one of the
β
hydrogen atom along with acting as a nucleophile.
C
H
3
−
C
H
2
−
C
H
2
−
C
H
3
|
C
|
C
l
−
C
H
3
+
N
a
+
O
C
H
3
2-chloro-2-methylpentane
C
H
2
O
H
→
C
H
3
C
H
2
−
H
|
C
=
C
H
3
|
C
−
C
H
3
+
C
H
3
O
H
+
N
a
B
r
2-Methyl-pent-2-ene
(a) and (c)
(c) only
(a) and (b)
All of these
Validate
Solution:
When tert -alkyl halides are used in Williamson synthesis elimination occurs rather than substitution resulting into formation af alkene. Here alkoxide jon abstract one of the
β
hydrogen atom along with acting as a nucleophile.
C
H
3
−
C
H
2
−
C
H
2
−
C
H
3
|
C
|
C
l
−
C
H
3
+
N
a
+
O
C
H
3
2-chloro-2-methylpentane
C
H
2
O
H
→
C
H
3
C
H
2
−
H
|
C
=
C
H
3
|
C
−
C
H
3
+
C
H
3
O
H
+
N
a
B
r
2-Methyl-pent-2-ene
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