Given, V=1.24 million volt =1.24×106 volt Since, energy (E)=eV where, e is the charge of electron =1.6×10−19C ∴E=1.6×10−19×1.24×106 ... (i) As we know that, Energy of photon, E=
hc
λ
...(ii) Here, Planck's constant, h=6.67×10−34J−s, C= speed of light in free space, C=3×108ms−1 Equating Eqs. (i) and (ii), we get 1.6×10−19×1.24×106=