32022 =(32)1011 =(9)1011 =(10−1)1011 =‌1011C0(10)1011+......+‌1011C1010⋅(10)1−‌1011C1011 =10[‌1011C0(10)1010+......+‌1011C1010]−1 =10K−1 [As 10[‌1011C0⋅(10)1010+......+‌1011C1010] is multiple of 10] =10K+5−5−1 =10K−5+5−1 =5(2K−1)+4 ∴ Unit digit =4 when divided by 5.