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JEE Main 24 June 2022 Shift 1 Solved Paper
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© examsnet.com
Question : 55
Total: 90
Sodium light of wavelengths
650
nm
and
655
nm
is used to study diffraction at a single slit of aperture
0.5
mm
. The distance between the slit and the screen is
2.0
m
. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is ______
×
10
−
5
m
.
[24-Jun-2022-Shift-1]
Your Answer:
Validate
Solution:
Position of
1
st
maxima is
3
2
λ
D
a
⇒
According to given values, required separation
=
3
2
×
(
655
nm
−
650
nm
)
×
2
m
0.5
mm
⇒
Required separation
=
3
×
10
−
5
m
.
© examsnet.com
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