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JEE Main 24 June 2022 Shift 1 Solved Paper
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© examsnet.com
Question : 61
Total: 90
If a rocket runs on a fuel
(
C
15
H
30
)
and liquid oxygen, the weight of oxygen required and
C
O
2
released for every litre of fuel respectively are :
(Given : density of the fuel is
0.756
g
∕
m
L
)
[24-Jun-2022-Shift-1]
1188
g
and
1296
g
2376
g
and
2592
g
2592
g
and
2376
g
3429
g
and
3142
g
Validate
Solution:
C
15
H
30
+
45
2
O
2
→
15
C
O
2
+
15
H
2
O
Given, volume of fuel
=
1
L
=
1000
m
l
And density of fuel
=
0.756
g
∕
m
l
We know,
d
=
w
v
⇒
0.756
=
w
1000
⇒
W
=
756
g
m
∴
weight of fuel
=
756
g
m
Molar mass of
C
15
H
30
=
15
×
12
+
30
=
210
∴
Moles of
C
15
H
30
=
756
210
From equation you can see,
1 mole of
C
15
H
30
react with
45
2
mole of
O
2
∴
756
210
moles of
C
15
H
30
react with
45
2
×
756
210
moles of
O
2
∴
Moles of
O
2
required
=
45
2
×
756
210
∴
Mass of
O
2
required
=
45
2
×
756
210
×
32
=
2592
g
Also,
From 1 mole of
C
15
H
30
15
moles of
C
O
2
formed
∴
From
756
210
moles of
C
15
H
30
15
×
756
210
moles of
C
O
2
formed
∴
Moles of
C
O
2
formed
=
15
×
756
210
∴
Mass of
C
O
2
formed
=
15
×
756
210
×
44
=
2376
g
© examsnet.com
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