Points A and B are at same horizontal level. So, the pressure at A and B will be equal i.e. pA=pB.... (i) If p0 is the atmospheric pressure, then from Bernoulli's theorem, pA=p0−
2T
rA
+(h+y)ρg pB=p0−
2T
rB
+ρgy Substituting the value of pA and pB in Eq. (i), we get p0−
2T
rA
+(h+y)ρg=p0−
2T
rB
+ρgy ⇒2T(
1
rB
−
1
rA
)=ρgy−(h+y)ρg ⇒2T(
1
rB
−
1
rA
)=−ρgh or2T(
1
rA
−
1
rB
)=cgh ...(ii) Here, rA=2.5mm=2.5×10−3m, and T=7.3×10−2N∕m, rB=4mm=4×10−3m,g=10m∕s2 and ρ=1×103kgm−3 Substituting the given value in Eq. (ii), we get h=