The given value of resistances are 2Ω,4Ω,6Ω and 8Ω. The required value of combination is
46
3
Ω. In order to achieve the above mentioned values of resistance from given resistances, we will connect 2Ω and 4Ω resistance in parallel, then join 6 Ω and 8 Ω resistance in series with the combination. The circuit diagram for connection is shown below.
∴Req=(2|4)+6+8=
2×4
2+4
+14=
46
3
Ω Thus, resistance of 2Ω and 4Ω are in parallel with 6Ω and 8Ω in series combination.