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JEE Main 26 June 2022 Shift 1 Solved Paper
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© examsnet.com
Question : 10
Total: 90
The area bounded by the curve
y
=
|
x
2
−
9
|
and the line
y
=
3
is :
[26-Jun-2022-Shift-1]
4
(
2
√
3
+
√
6
−
4
)
4
(
4
√
3
+
√
6
−
4
)
8
(
4
√
3
+
3
√
6
−
9
)
8
(
4
√
3
+
√
6
−
9
)
Validate
Solution:
👈: Video Solution
y
=
3
and
y
=
|
x
2
−
9
|
Intersect in first quadrant at
x
=
√
6
and
x
=
√
12
Required area
=
2
[
2
3
(
6
×
√
6
)
+
∫
√
6
3
(
3
−
(
9
−
x
2
)
)
d
x
+
∫
3
√
12
(
3
−
(
x
2
−
9
)
)
d
x
]
=
2
[
4
√
6
+
.
(
x
3
3
−
6
x
)
|
√
6
3
+
.
(
12
x
−
x
3
3
)
|
3
√
12
]
=
2
[
4
√
6
+
(
4
√
6
−
9
)
+
(
8
√
12
−
27
)
]
=
2
[
8
√
6
+
16
√
3
−
36
]
=
8
[
2
√
6
+
4
√
3
−
9
]
© examsnet.com
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