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JEE Main 26 June 2022 Shift 1 Solved Paper
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© examsnet.com
Question : 26
Total: 90
If
sin
2
(
10
∘
)
sin
(
20
∘
)
sin
(
40
∘
)
sin
(
50
∘
)
sin
(
70
∘
)
=
α
−
1
16
sin
(
10
∘
)
, then
16
+
α
−
1
is equal to____
[26-Jun-2022-Shift-1]
Your Answer:
Validate
Solution:
👈: Video Solution
(
sin
10
∘
⋅
sin
50
∘
⋅
sin
70
∘
)
⋅
(
sin
10
∘
⋅
sin
20
∘
⋅
sin
40
∘
)
=
(
1
4
sin
30
∘
)
⋅
[
1
2
sin
10
∘
(
cos
20
∘
−
cos
60
∘
)
]
=
1
16
[
sin
10
∘
(
cos
20
∘
−
1
2
)
]
=
1
32
[
2
sin
10
∘
⋅
cos
20
∘
−
sin
10
∘
]
=
1
32
[
sin
30
∘
−
sin
10
∘
−
sin
10
∘
]
=
1
64
−
1
64
sin
10
∘
Clearly,
α
=
1
64
Hence
16
+
α
−
1
=
80
© examsnet.com
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