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JEE Main 26 June 2022 Shift 2 Solved Paper
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© examsnet.com
Question : 26
Total: 90
If
(
40
C
0
)
+
(
41
C
1
)
+
(
42
C
2
)
+
.
.
.
.
.
.
+
(
60
C
20
)
=
m
n
60
C
20
, m and
n
are coprime, then
m
+
n
is equal to____
[26-Jun-2022-Shift-2]
Your Answer:
Validate
Solution:
👈: Video Solution
Here property used is
n
C
r
+
n
C
r
+
1
=
n
+
1
C
r
+
1
Given,
40
C
0
+
41
C
1
+
42
C
2
+
.
.
.
+
60
C
20
=
m
n
60
C
20
As
40
C
0
=
41
C
0
=
1
So, we replace
40
C
0
with
41
C
0
.
⇒
41
C
0
+
41
C
1
+
42
C
2
+
.
.
.
.
.
.
+
60
C
20
=
m
n
⋅
60
C
20
⇒
42
C
1
+
42
C
2
+
.
.
.
.
.
.
+
60
C
20
=
m
n
⋅
60
C
20
⇒
43
C
2
+
43
C
3
+
.
.
.
.
.
.
+
60
C
20
=
m
n
⋅
60
C
20
⇒
44
C
3
+
44
C
4
+
.
.
.
.
.
.
+
60
C
20
=
m
n
⋅
60
C
20
⇒
45
C
4
+
45
C
5
+
.
.
.
.
.
.
+
60
C
20
=
m
n
⋅
60
C
20
⋮
⇒
60
C
19
+
60
C
20
=
m
n
⋅
60
C
20
⇒
61
C
20
=
m
n
⋅
60
C
20
⇒
61
!
20
!
41
!
=
m
n
⋅
60
!
20
!
40
!
⇒
61
41
=
m
n
∴
m
=
61
and
n
=
41
∴
m
+
n
=
61
+
41
=
102
© examsnet.com
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