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JEE Main 26 June 2022 Shift 2 Solved Paper
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© examsnet.com
Question : 4
Total: 90
lim
x
→
0
cos
(
sin
x
)
−
cos
x
x
4
is equal to :
[26-Jun-2022-Shift-2]
1
3
1
4
1
6
1
12
Validate
Solution:
👈: Video Solution
lim
x
→
0
cos
(
sin
x
)
−
cos
x
x
4
=
lim
x
→
0
2
sin
(
x
+
sin
x
)
⋅
sin
(
x
−
sin
x
2
)
x
4
=
lim
x
→
0
2
⋅
(
(
x
+
sin
x
2
)
(
x
−
sin
x
2
)
x
4
)
=
lim
x
→
0
1
2
⋅
(
(
x
+
x
−
x
3
3
!
+
x
5
5
!
.
.
.
)
(
x
−
x
+
x
3
3
!
.
.
.
)
x
4
)
=
lim
x
→
0
1
2
⋅
(
2
−
x
2
3
!
+
x
4
5
!
.
.
.
)
(
1
3
!
−
x
2
5
!
−
1
)
=
1
6
© examsnet.com
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