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JEE Main 26 June 2022 Shift 2 Solved Paper
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© examsnet.com
Question : 51
Total: 90
A ball is projected vertically upward with an initial velocity of
50
ms
−
1
at
t
=
0
s. At
t
=
2
s
, another ball is projected vertically upward with same velocity. At
t
=
_______
s
, second ball will meet the first ball
(
g
=
10
ms
−
2
)
.
[26-Jun-2022-Shift-2]
Your Answer:
Validate
Solution:
Let they meet at
t
=
t
So first ball gets
t
sec.
&
2
nd
gets
(
t
−
2
)
sec. \& they will meet at same
height
h
1
=
50
t
−
1
2
gt
2
h
2
=
50
(
t
−
2
)
−
1
2
g
(
t
−
2
)
2
h
1
=
h
2
50
t
−
1
2
gt
2
=
50
(
t
−
2
)
−
1
2
g
(
t
−
2
)
2
100
=
1
2
g
[
t
2
−
(
t
−
2
)
2
]
100
=
10
2
[
4
t
−
4
]
5
=
t
−
1
t
=
6
sec
.
© examsnet.com
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