As we know that, the dimensional formula of density [D]=[ML−3T0] Since, dimensional formula of force [F]=[MLT−2] Dimensional formula of length [L]=[M0L1T0] Dimensional formula of time [T]=[M0L0T1] ∴[D]=[F]a[Lb[T]c ⇒[ML−3T0]=[ML−2]a [M0L1T0]b[M0L0T1]c =[MaLa+bT−2a+c] Comparing powers of dimensions on both sides, we get ca=1 a+b=−3 ⇒b=−3−1=−4 and −2a+c=0 c=2a ⇒c=2×1=2 ∴ Dimensional formula of density will be [F1L−4T2].