According to the given figure, and free body diagram
masses of two bodies m1=2kgm2=8kg , Acceleration of mass m1=a Acceleration of mass m2=‌
a
2
Tension =T Distance between m2 and ground =20cm =0.2m Initial velocity u=0 Equation of motion of 2kg block, ∴‌‌T−2g=2a‌‌‌⋅⋅⋅⋅⋅⋅⋅(i)
Equation of motion of 8kg block, and 8g−2T=8‌
a
2
⇒4g−T=2a‌‌‌⋅⋅⋅⋅⋅⋅⋅(ii) From Eqs. (i) and (ii), ⇒‌‌T−2g=4g−T ‌ Substituting the value in Eq. (i) we get ‌ ‌‌3g−2g=2a⇒g=2a ⇒‌‌a=‌