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JEE Main 27 June 2022 Shift 2 Solved Paper
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© examsnet.com
Question : 16
Total: 90
The mean and variance of the data
4
,
5
,
6
,
6
,
7
,
8
,
x
,
y
, where
x
<
y
, are 6 and
9
4
respectively. Then
x
4
+
y
2
is equal to
[27-Jun-2022-Shift-2]
162
320
674
420
Validate
Solution:
Mean
=
4
+
5
+
6
+
6
+
7
+
8
+
x
+
y
8
=
6
∴
x
+
y
=
12
.
.
.
.
(i)
And variance
=
2
2
+
1
2
+
0
2
+
0
2
+
1
2
+
2
2
+
(
x
−
6
)
2
+
(
y
−
6
)
2
8
=
9
4
∴
(
x
−
6
)
2
+
(
y
−
6
)
2
=
8
.
.
.
.
(ii)
From (i) and (ii)
x
=
4
and
y
=
8
∴
x
4
+
y
2
=
320
© examsnet.com
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