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JEE Main 27 June 2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 2

Total: 90

Let f(x)=|

a	−1	0
ax	a	−1
ax2	ax	a

|,a∈R. Then the sum of the squares of all the values of a, for which 2f′(10)−f′(5)+100=0, is

[27-Jun-2022-Shift-2]

117
106
125
136

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