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JEE Main 27 June 2022 Shift 2 Solved Paper
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© examsnet.com
Question : 48
Total: 90
Given below are two statements :
Statement I : In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit (E
.
E
1
)
to higher energy orbit
(
E
2
)
, is given as
h
f
=
E
1
−
E
2
Statement II : The jumping of electron from higher energy orbit
(
E
2
)
to lower energy orbit
(
E
1
)
is associated with frequency of radiation given as
f
=
(
E
2
−
E
1
)
∕
h
This condition is Bohr's frequency condition.
In the light of the above statements, choose the correct answer from the options given below :
[27-Jun-2022-Shift-2]
Both Statement I and Statement II are true.
Both Statement I and Statement II are false.
Statement I is correct but Statement II is false.
Statement I is incorrect but Statement II is true.
Validate
Solution:
Radiation is not emitted but absorbed when an electron jumps from low energy to high energy.
Also,
E
2
−
E
1
is the energy of photon
⇒
E
2
−
E
1
=
hf
⇒
f
=
E
2
−
E
1
h
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