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JEE Main 28 June 2022 Shift 2 Solved Paper
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© examsnet.com
Question : 24
Total: 90
If
lim
x
→
1
sin
(
3
x
2
−
4
x
+
1
)
−
x
2
+
1
2
x
3
−
7
x
2
+
a
x
+
b
=
−
2
, then the value of
(
a
−
b
)
is equal to____
[28-Jun-2022-Shift-2]
Your Answer:
Validate
Solution:
lim
x
→
1
(
s
i
n
(
3
x
2
−
4
x
+
1
)
3
x
2
−
4
x
+
1
)
(
3
x
2
−
4
x
+
1
)
−
x
2
+
1
2
x
3
−
7
x
2
+
a
x
+
b
=
−
2
⇒
lim
x
→
1
3
x
2
−
4
x
+
1
−
x
2
+
1
2
x
3
−
7
x
2
+
a
x
+
b
=
−
2
⇒
lim
x
→
1
2
(
x
−
1
)
2
2
x
3
−
7
x
2
+
a
x
+
b
=
−
2
So
f
(
x
)
=
2
x
3
−
7
x
2
+
a
x
+
b
=
0
has
x
=
1
as repeated root, therefore
f
(
1
)
=
0
and
f
′
(
1
)
=
0
gives
a
+
b
+
5
and
a
=
8
So,
a
−
b
=
11
© examsnet.com
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