z1985+z100+1=0&z3+2z2+2z+1=0 ‌(z+1)(z2−z+1)+2z(z+1)=0 ‌(z+1)(z2+z+1)=0 ⇒‌‌z=−1,‌‌z=w,w2 Now putting z=−1 not satisfy Now put z=w ‌⇒‌‌w1985+w100+1 ‌⇒‌‌w2+w+1=0 ‌‌ Also, ‌z=w2 ⇒‌‌w3970+w200+1 ⇒‌‌w+w2+1=0 Two common root