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JEE Main 30 June 2022 Shift 1 Solved Paper
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© examsnet.com
Question : 2
Total: 90
The real part of the complex number
(
1
+
2
i
)
8
⋅
(
1
−
2
i
)
2
(
3
+
2
i
)
⋅
(
4
−
6
i
)
is equal to:
[30-Jun-2022-Shift-1]
500
13
110
13
55
6
550
13
Validate
Solution:
👈: Video Solution
Given,
(
1
+
2
i
)
8
⋅
(
1
−
2
i
)
2
(
3
+
2
i
)
⋅
(
4
−
6
i
)
=
(
1
+
2
i
)
2
(
1
−
2
i
)
2
(
1
+
2
i
)
6
(
3
+
2
i
)
(
4
+
6
i
)
=
(
1
−
4
i
2
)
2
(
1
+
2
i
)
6
12
+
18
i
+
8
i
+
12
i
2
=
(
1
+
5
)
2
[
(
1
+
2
i
)
2
]
3
12
+
26
i
−
12
=
25
(
1
+
4
i
2
+
4
i
)
3
26
i
=
25
(
1
−
4
+
4
i
)
3
26
i
=
25
(
−
3
+
4
i
)
3
26
i
=
25
26
i
[
(
−
3
)
3
+
(
4
i
)
3
+
3
⋅
(
−
3
)
2
⋅
4
i
+
3
(
−
3
)
⋅
(
4
i
)
2
]
=
25
26
i
(
−
27
−
64
i
+
108
i
+
144
)
=
25
26
i
(
117
+
44
i
)
=
25
i
26
i
2
(
117
+
44
i
)
=
25
i
−
26
(
117
+
44
i
)
=
25
×
117
i
−
26
−
25
×
44
i
2
26
=
25
×
117
i
−
26
+
22
×
25
13
=
25
×
117
i
−
26
+
550
13
∴
Real part
=
550
13
© examsnet.com
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