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JEE Main 4 Apr 2024 Shift 1 Solved Paper
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© examsnet.com
Question : 24
Total: 90
If the shortest distance between the lines
x
+
2
2
=
y
+
3
3
=
z
−
5
4
and
x
−
3
1
=
y
−
2
−
3
=
z
+
4
2
is
38
3
√
5
k
and
k
∫
0
[
x
2
]
dx
=
α
−
√
α
, where
[
x
]
denotes the greatest integer function, then
6
α
3
is equal to _______
[4 Apr 2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
38
3
√
5
^
k
=
(
5
^
i
+
5
^
j
−
9
^
k
)
√
5
⋅
|
^
i
^
j
^
k
2
3
4
1
−
3
2
|
38
3
√
5
^
k
=
19
√
5
k
=
19
√
5
k
=
3
2
3
∕
2
∫
0
[
x
2
]
=
1
∫
0
0
+
√
2
∫
1
1
+
3
∕
2
∫
√
2
2
=
√
2
−
1
+
2
(
3
2
−
√
2
)
=
2
−
√
2
α
=
2
⇒
6
α
3
=
48
© examsnet.com
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