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JEE Main 6 Apr 2024 Shift 1 Solved Paper
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© examsnet.com
Question : 37
Total: 89
While measuring diameter of wire using screw gauge the following readings were noted. Main scale reading is
1
mm
and circular scale reading is equal to 42 divisions. Pitch of screw gauge is
1
mm
and it has 100 divisions on circular scale. The diameter of the wire is
x
50
mm
. The value of
x
is :
[6 Apr 2024 Shift 1]
142
71
42
21
Validate
Solution:
👈: Video Solution
MSR
=
1
mm
,
CSR
=
42
,
pitch
=
1
mm
LC
=
pitch
No. of
CSD
=
(
1
100
)
=
0.01
mm
Diameter
=
MSR
+
LC
×
CSD
Diameter
=
1
+
(
0.01
)
×
42
mm
Diameter
=
1.42
mm
=
x
50
∴
x
=
71
© examsnet.com
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