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JEE Main 6 Apr 2024 Shift 1 Solved Paper
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© examsnet.com
Question : 54
Total: 89
When a dc voltage of
1100
V
is applied to an inductor, a dc current of
5
A
flows through it. When an ac voltage of
200
V
peak value is connected to inductor, its inductive reactance is found to be
20
√
3
Ω
. The power dissipated in the circuit is ______ W.
[6 Apr 2024 Shift 1]
Your Answer:
Validate
Solution:
👈: Video Solution
For
DC
voltage
R
=
V
I
=
100
5
=
20
Ω
for AC voltage
X
L
=
20
√
3
Ω
R
=
20
Ω
Z
=
√
X
L
2
+
R
2
=
√
3
×
400
+
400
=
40
Ω
Power
=
i
rms
2
R
=
(
V
rms
Z
)
2
×
R
=
(
200
√
2
40
)
2
×
20
=
250
W
© examsnet.com
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