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JEE Main 6 Apr 2024 Shift 2 Solved Paper

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Question : 32

Total: 90

A total of 48J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by 2∘C. The work done by the gas is : (Given, R=8.3JK−1mol−1.)

[6 Apr 2024 Shift 2]

72.9J
24.9J
48J
23.1J

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