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JEE Main 6 Apr 2024 Shift 2 Solved Paper
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© examsnet.com
Question : 4
Total: 90
Suppose the solution of the differential equation
d
y
d
x
=
(
2
+
α
)
x
−
β
y
+
2
β
x
−
2
α
y
−
(
β
γ
−
4
α
)
represents a circle passing through origin. Then the radius of this circle is :
[6 Apr 2024 Shift 2]
√
17
1
2
√
17
2
2
Validate
Solution:
👈: Video Solution
d
y
d
x
=
(
2
+
α
)
x
−
β
y
+
2
β
x
−
y
(
2
α
+
β
)
+
4
α
β
x
d
y
−
(
2
α
+
β
)
y
d
y
+
4
α
d
y
=
(
2
+
α
)
x
dx
−
β
y
dx
+
2
dx
β
(
x
d
y
+
y
dx
)
−
(
2
α
+
β
)
y
d
y
+
4
α
d
y
=
(
2
+
α
)
x
dx
+
2
dx
β
x
y
−
(
2
α
+
β
)
y
2
2
+
4
α
y
=
(
2
+
α
)
x
2
2
⇒
β
=
0
for this to be circle
(
2
+
α
)
x
2
2
+
α
y
2
+
2
x
−
4
α
y
=
0
coeff. of
>
2
+
a
=
2
a
x
2
=
y
2
>
2
⇒
α
=
2
i.e.
2
x
2
+
2
y
2
+
2
x
−
8
y
=
0
x
2
+
y
2
+
x
−
4
y
=
0
rd
=
√
1
4
+
4
=
√
17
2
© examsnet.com
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