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JEE Main 6 Apr 2024 Shift 2 Solved Paper
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© examsnet.com
Question : 50
Total: 90
A body projected vertically upwards with a certain speed from the top of a tower reaches the ground in
t
1
. If it is projected vertically downwards from the same point with the same speed, it reaches the ground in
t
2
. Time required to reach the ground, if it is dropped from the top of the tower, is :
[6 Apr 2024 Shift 2]
√
t
1
t
2
√
t
1
−
t
2
√
t
1
t
2
√
t
1
+
t
2
Validate
Solution:
👈: Video Solution
t
1
=
u
+
√
u
2
+
2
g
h
g
t
2
=
−
u
+
√
u
2
+
2
g
h
g
t
=
√
2
g
h
g
t
1
t
2
=
(
u
2
+
2
g
h
)
−
u
2
g
2
=
2
g
h
g
2
=
t
2
⇒
t
=
√
t
1
t
2
© examsnet.com
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