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JEE Main 6 Apr 2024 Shift 2 Solved Paper
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© examsnet.com
Question : 7
Total: 90
Let
0
≤
r
≤
n
. If
n
+
1
C
r
+
1
:
n
C
r
:
n
−
1
C
r
−
1
=
55
:
35
:
21
, then
2
n
+
5
r
is equal to:
[6 Apr 2024 Shift 2]
60
62
50
55
Validate
Solution:
👈: Video Solution
n
+
1
C
r
n
C
r
=
55
35
(
n
+
1
)
!
(
r
+
1
)
!
(
n
−
r
)
!
r
!
(
n
−
r
)
!
n
!
=
11
7
(
n
+
1
)
r
+
1
=
11
7
7
n
=
4
+
11
r
n
C
r
n
−
1
C
r
=
35
21
n
!
r
!
(
n
−
r
)
!
=
(
r
−
1
)
!
(
n
−
r
)
!
(
n
−
1
)
!
=
5
3
n
r
=
5
3
3
n
=
5
r
By solving
r
=
6
n
=
10
2
n
+
5
r
=
50
© examsnet.com
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