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JEE Main 8 Apr 2024 Shift 1 Solved Paper
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© examsnet.com
Question : 50
Total: 90
The diameter of a sphere is measured using a vernier caliper whose 9 divisions of main scale are equal to 10 divisions of vernier scale. The shortest division on the main scale is equal to
1
mm
. The main scale reading is
2
cm
and second division of vernier scale coincides with a division on main scale. If mass of the sphere is
8.635
g
, the density of the sphere is:
[8 Apr 2024 Shift 1]
2.5
g
∕
cm
3
1.7
g
∕
cm
3
2.2
g
∕
cm
3
2.0
g
∕
cm
3
Validate
Solution:
👈: Video Solution
Given
9
MSD
=
10
VSD
mass
=
8.635
g
LC
=
1
MSD
−
1
VSD
LC
=
1
MSD
−
9
10
MSD
LC
=
1
10
MSD
LC
=
0.01
cm
Reading of diameter
=
MSR
+
LC
×
VSR
=
2
cm
+
(
0.01
)
×
(
2
)
=
2.02
cm
Volume of sphere
=
4
3
π
(
d
2
)
3
=
4
3
π
(
2.02
2
)
3
=
4.32
cm
3
Density
=
mass
volume
=
8.635
4.32
=
1.998
∼
2.00
g
© examsnet.com
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