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JEE Main 8 Apr 2024 Shift 1 Solved Paper
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© examsnet.com
Question : 7
Total: 90
Let
f
(
x
)
=
4
cos
3
x
+
3
√
3
cos
2
x
−
10
. The number of points of local maxima of
f
in interval
(
0
,
2
π
)
is:
[8 Apr 2024 Shift 1]
1
2
3
4
Validate
Solution:
👈: Video Solution
f
(
x
)
=
4
cos
3
(
x
)
+
3
√
3
cos
2
(
x
)
−
10
;
x
∈
(
0
,
2
π
)
⇒
f
′
(
x
)
=
12
cos
2
x
[
−
s
i
n
(
x
)
]
+
3
√
3
(
2
cos
(
x
)
)
[
−
s
i
n
(
x
)
]
⇒
f
′
(
x
)
=
−
6
s
i
n
(
x
)
cos
(
x
)
[
2
cos
(
x
)
+
√
3
]
local maxima at
x
=
5
π
6
,
7
π
6
© examsnet.com
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