A={2,3,6,8,9,11}(a,b)R(c,d)
B={1,4,5,10,15}3ad−7bc
Reflexive : (a, b) R(a, b)
⇒3ab−7ba=−4ab always even so it is reflexive.
Symmetric : If 3ad−7bc= Even
Case-I : odd odd
Case-II: even even
(c,d)R(a,b)⇒3bc−3ab
Case-I : odd odd
Case-II : even even
so symmetric relation
Transitive :
Set (3,4)R(6,4) Satisfy relation
Set (6,4)R(3,1) Satisfy relation
but (3,4)R(3,1) does not satisfy relation so not transitive.
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