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JEE Main 8 Apr 2024 Shift 2 Solved Paper
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© examsnet.com
Question : 56
Total: 90
Two slits are
1
mm
apart and the screen is located
1
m
away from the slits. A light wavelength
500
nm
is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is
.
.
.
.
.
.
.
.
.
.
×
10
−
4
m
.
[8 Apr 2024 Shift 2]
Your Answer:
Validate
Solution:
👈: Video Solution
d
=
1
mm
,
D
=
1
m
,
λ
=
500
nm
10
(
λ
D
d
)
=
2
λ
D
a
a
=
d
5
=
10
×
10
−
4
m
5
=
2
×
10
−
4
© examsnet.com
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