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JEE Main 8 Apr 2024 Shift 2 Solved Paper
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© examsnet.com
Question : 58
Total: 90
A potential divider circuit is connected with a dc source of
20
V
, a light emitting diode of glow in voltage
1.8
V
and a zener diode of breakdown voltage of
3.2
V
. The length (PR) of the resistive wire is
20
cm
. The minimum length of
P
Q
to just glow the LED is ............. cm.
[8 Apr 2024 Shift 2]
Your Answer:
Validate
Solution:
👈: Video Solution
PR
=
20
cm
V
PQ
=
1
4
×
R
PR
ℓ
min
(
PQ
)
=
1
4
×
20
=
5
cm
© examsnet.com
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